What is the product of (3a + 2)(4a2 – 2a + 9)?
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Answer:
product of (3a+2)((4a²-2a+9)
= 12a³+2a²+23a+18
Explanation:
Product of (3a+2)(4a²-2a+9)
=3a(4a²-2a+9)+2(4a²-2a+9)
= 12a³-6a²+27a+8a²-4a+18
Rearranging the like terms at one place, we get
= 12a³-6a²+8a²+27a-4a+18
= 12a³+(-6+8)a²+(27-4)a+18
= 12a³+2a²+23a+18
Therefore,
(3a+2)((4a²-2a+9)
= 12a³+2a²+23a+18
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