What is the product of electrolysis of lead oxide
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At cathode, a lead (ll) ion accepts two electrons to form a lead atom. At anode, an oxide ion releases two electrons to form an oxygen atom. Two oxygen atoms combine to form one molecule of oxygen gas.
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Answer:
the half- equation for the electrolysis of lead (ll) bromide. this is a reduction reaction because the lead ions gain electrons. the negative bromide ions are attached to the positive anode electrode and discharged to from bromime vapour. this is an oxidation reaction because the brominde ions lose electrons
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