Math, asked by StAnslemPinkcity, 1 year ago

What is the product of unit digit in 7^95 - 3^58 and 7^95 + 3^58???

U have to answer.Don't surrender.
I will mark as brainliest.
Best of luck my friends!!!

Answers

Answered by tejasri2
10
the unit digit in 7^95 is

95 / 4= 23
and leaves remainder 3
the unit digit in 7^ 3 is unit digit in 7^95

the unit digit in 7^95 = 7^ 3 = 3

similarly the unit digit in 3 ^ 58 = 3² = 9

the unit digit in 7^95 - 3 ^ 58 = 4

similarly the unit digit in 7^95 + 3 ^ 58 = 1

here is ur answer

I hope it helps you

plz brainliest

tejasri2: okk
StAnslemPinkcity: This is not fair
tejasri2: I thought my answer is right
tejasri2: so I asked for brainliest
tejasri2: ok
tejasri2: already u have complained
tejasri2: so leave it
tejasri2: :-)
tejasri2: bye
madhivadhanans: Haha
Answered by mathumsp7
9

Answer:

Step-by-step explanation:the unit digit in7^95 is 3 as (7^4)7^3 and the unit digit in 3^58 is 9 as(3^4)3^2. So u get 3-9 for the 3 you have to borrow 10 from the before digit and thus it becomes 13 and 9.so on subration u get 4.bt on addition u no need to borrow u get answer as 12.

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