What is the product of unit digit in 7^95 - 3^58 and 7^95 + 3^58???
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Answers
Answered by
10
the unit digit in 7^95 is
95 / 4= 23
and leaves remainder 3
the unit digit in 7^ 3 is unit digit in 7^95
the unit digit in 7^95 = 7^ 3 = 3
similarly the unit digit in 3 ^ 58 = 3² = 9
the unit digit in 7^95 - 3 ^ 58 = 4
similarly the unit digit in 7^95 + 3 ^ 58 = 1
here is ur answer
I hope it helps you
plz brainliest
95 / 4= 23
and leaves remainder 3
the unit digit in 7^ 3 is unit digit in 7^95
the unit digit in 7^95 = 7^ 3 = 3
similarly the unit digit in 3 ^ 58 = 3² = 9
the unit digit in 7^95 - 3 ^ 58 = 4
similarly the unit digit in 7^95 + 3 ^ 58 = 1
here is ur answer
I hope it helps you
plz brainliest
tejasri2:
okk
Answered by
9
Answer:
Step-by-step explanation:the unit digit in7^95 is 3 as (7^4)7^3 and the unit digit in 3^58 is 9 as(3^4)3^2. So u get 3-9 for the 3 you have to borrow 10 from the before digit and thus it becomes 13 and 9.so on subration u get 4.bt on addition u no need to borrow u get answer as 12.
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