Question

what is the product roots of x^2 - 5x + 6 =0 ​

Answer 1

Answer:

$\huge\tt{\bigstar{\underline{\underline{\red{SOLUTION}}}}}$

$→product \: of \: zeros = \frac{c}{a} \\ \\ → c = 6. \: \: a = 1 \\ \\ →by \: putting \: the \: value \: of \: a \: and \: b \\ \\→ \frac{6}{1} \\ \\ → 6 \\ \\→ verification \\ \\ →{x}^{2} - 5x + 6 \\ \\ → {x}^{2} -3x - 2x + 6 \\ \\ →x(x - 3) - 2(x - 3) \\ \\→ (x - 2)(x - 3) \\ \\→ zeros = > \\ \\→(i) x - 2 = 0 \\ \\→ x = 2 \\ \\ (ii)→x - 3 = 0 \\ \\ →x = 3 \\ \\ →produvt \: of \: zero \: = > \\ \\ 2 \times 3 = 6 \\ \\ \\ hence \: verified$

Answer 2

HERE IS UR ANSWER DEAR,

$x {}^{2} - 5 x + 6 = 0$

$here$

$sum = - 5$

$product = 6$

$hence \: \: it \:may \: be \: written \: as$

$x {}^{2} + ( (- 3 )+ (- 2) )x+ ( - 3 \times - 2) = 0$

$(x - 2)(x - 3) = 0$

$(x - 2) = 0 \: \: \: \: : \: (x - 3) = 0$

$x = 2 \: \: \: : \: \: x = 3$

therefore ,

2 and 3 are the roots of the polynomial..

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