Question

what is the Pythagorean triplet whose one member is 17

Answer 1

15 and 8

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Explanation:

15^2+8^2=17^2

following the law of Pythagorean triplet

Answer 2

We know that for a natural number n > 1, (2, m^2 - 1, m^2 + 1) form a pythagorean triplet.

Now,

= > m^2 + 1 = 17

= > m^2 = 17 - 1

= > m^2 = 16

= > m = 4.

Then,

= > 2m = 8

= > m^2 + 1 = (4)^2 + 1 = 17.

= > m^2 - 1 = (4)^2 - 1 = 15.

Therefore, the required triplet is 8,15,17.

Hope this helps!