What is the quadratic equation whose one of the roots is 3 - √5
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Answer:
k(x^2-6x+4)
Step-by-step explanation:
as one root is irrational other must be it's conjugate
so 3-√5 and 3+√5 are the roots
quadratic equation = k(x-(3-√5))(x-(3+√5))....where k is a constant
k(x-3+√5)(x-3-√5)
k(x^2-3x-√5x-3x+9+3√5+√5x-3√5-5)
k(x^2-6x+4)
hope it helps u
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