What is the quadratic polynomial, the sum and product of whose zeroes are -1/2 and -3 respectively?
Answers
Answered by
2
Hi Friend !!!
Here is ur answer !!!
Quadratic polynomial
= x²-(sum of zeroes) x + (product of zeroes)
= x²-(-1/2)x+(-3)
= x²+1/2 x-3
= 2x²+x-6
Hope it helps u : )
Here is ur answer !!!
Quadratic polynomial
= x²-(sum of zeroes) x + (product of zeroes)
= x²-(-1/2)x+(-3)
= x²+1/2 x-3
= 2x²+x-6
Hope it helps u : )
mysticd:
What about LCM 2
the equation has to be multiplied by to to remove it
form k [x² - ( sum of the zeroes)x + product of the zeroes ]
yaa
for real values of k , polynomial is true
if k = 2 , then we get the answer .
yaa
Answered by
1
Heya !!!
Sum of zeroes = -1/2
And,
Product of zeroes = -3
Therefore,
Required Quadratic polynomial = X²-(Sum of zeroes)X + Product of zeroes
=> X²-(-1/2)X + (-3) = 0
=> X²+X/2- 3 = 0
=> 2X² + X - 6/2 = 0
=2X² + X -6 = 0 × 2
=> 2X² + X -6
HOPE IT WILL HELP YOU..... :-)
Sum of zeroes = -1/2
And,
Product of zeroes = -3
Therefore,
Required Quadratic polynomial = X²-(Sum of zeroes)X + Product of zeroes
=> X²-(-1/2)X + (-3) = 0
=> X²+X/2- 3 = 0
=> 2X² + X - 6/2 = 0
=2X² + X -6 = 0 × 2
=> 2X² + X -6
HOPE IT WILL HELP YOU..... :-)
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