Question

what is the quadratic polynomial , the sum and product of whose zeroes are -1/2and -3 respectively? ​

Answer 1

Answer:

2*(x^2) + x - 6

Step-by-step explanation:

p(x) = x^2−(sum−of−roots)*x+(product−of−roots)

= x^2 -(-1/2)*x + (-3)

multiplying the whole equation by 2, ti simplify it

= 2*(x^2) + x - 6

Answer 2

Given : the sum and product of zeroes of the polynomials are -1/2 and -3 respectively

To Find: the polynomial

Solution:

Polynomial = k ( x² - (sum of zeroes) x   + Product of zeroes)

k is non zero real number

sum of zeroes = -1/2

Product of zeroes = -3

Polynomial = k  (x² - (-1/2)x  + (-3))

= k(x² + x/2 - 3 )

Using k = 2

2x²  + x -  6

Hence 2x² +  x -  6 is one polynomial having  sum and product of zeroes   -1/2 and -3 respectively

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