what is the quadratic polynomial whose sum of zeros is 5/3 and the product of zeros is 1
Answers
Answered by
6
Heya !
Sum of zeroes = 5/3
and,
Product of zeroes = 1
Therefore,
Quadratic polynomial = X²-(Sum of zeroes)X + Product of zeroes
=> X² - (5/3)X + 1
=> X² - 5X/3 + 1
=> 3X² - 5X + 3
Hence,
Required quadratic polynomial = 3X² - 5X + 3
Sum of zeroes = 5/3
and,
Product of zeroes = 1
Therefore,
Quadratic polynomial = X²-(Sum of zeroes)X + Product of zeroes
=> X² - (5/3)X + 1
=> X² - 5X/3 + 1
=> 3X² - 5X + 3
Hence,
Required quadratic polynomial = 3X² - 5X + 3
aravind200423:
thanks
Answered by
6
Hey dear!!!
___________________________
==>>> Solution
Let the zeroes of the unknown quadratic polynomial be α and β .
According to the given data we have,
Sum of zeroes (α + β) = 5/3
and
Product of zeroes (αβ) = 1
We have to find the required quadratic polynomial .
We know that,
=> x² - (sum of zeroes(α +β)x + (product of zeroes(αβ)
Now,put the obtained values we get,
=> x² - (5/3)x + 1
=> x² - 5x/3 + 1
Now multiply the whole equation by 3 we get,
=> 3*x² - 3*5x/3 + 3*1
3 and another 3 which have in the denominator got cancelled .
Hence,
=> 3x² - 5x + 3
∴ The required quadratic polynomial is 3x² - 5x + 3
Thanks !!!!
✴✴✴✴✴✴ R.N.S✴✴✴✴✴✴✴✴
___________________________
==>>> Solution
Let the zeroes of the unknown quadratic polynomial be α and β .
According to the given data we have,
Sum of zeroes (α + β) = 5/3
and
Product of zeroes (αβ) = 1
We have to find the required quadratic polynomial .
We know that,
=> x² - (sum of zeroes(α +β)x + (product of zeroes(αβ)
Now,put the obtained values we get,
=> x² - (5/3)x + 1
=> x² - 5x/3 + 1
Now multiply the whole equation by 3 we get,
=> 3*x² - 3*5x/3 + 3*1
3 and another 3 which have in the denominator got cancelled .
Hence,
=> 3x² - 5x + 3
∴ The required quadratic polynomial is 3x² - 5x + 3
Thanks !!!!
✴✴✴✴✴✴ R.N.S✴✴✴✴✴✴✴✴
Similar questions