Question

What is the quantity of NaOH present in 250 cc of
the solution, so that it gives a pH = 13:-
​

Answer 1

Answer:

If pH =13, the poH= 14-13=1

If pOH =1 , [OH–]=10-pOH=0.10

Since NaOH=0.10M Then:

0.10mol/L×0.250 L

=0.025molNaOH

Mass of NaOH=0.025 mol ×40g/mol

=1gNaOH