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2) 72 cm²
Step-by-step explanation:
Let ABCD and PQRS be the cross roads,
AB= 2cm.
BC= 20cm.
Area of path ABCD=(AB×BC)cm²
=(2×20)cm²
=40cm².
PQ=4cm.
QR=10cm.
Area of path PQRS= (PQ×QR)cm²
=(4×10)cm²
=40cm².
Area EFGH is common to the both the paths.
EF= 4cm.
FG= 2cm.
Area if EFGH=(EF×GH)cm²
=(4×2)cm²
=8cm².
Total Area covered as roads=
=(Area of road ABCD+Area of road PQRS- Area of road EFGH.)
=(40+40-8)cm²
=72cm².
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