Question

What is the radius and curved surface area of a cone made from a quadrant of a circle of radius 28 cm?​

Answer 1

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$\huge\mathcal\pink{Solution:-}$

⛄ ANSWER:-

→Radius of the cone = 7 cm.

→CSA of the cone= 616 cm².

⛄ STEP-BY-STEP EXPLAINATION:-

❄ Given:-

A quadrant of a circle is folded to make a cone. Radius of the circle= 28 cm.

❄ To find:-

Radius and CSA of the new cone.

❄ Solution:-

Let R be the radius of the cone and r be the radius of the circle.

Now,

Since the quadrant of the circle is folded to form a cone, the circumference of the cone would be the area of the arc of the quadrant.

Thus,

2πr of the cone= Area of the arc of the quadrant. [i.e. 1/4 × circumference of the circle]

=> 2πR = 1/4 × 2πr

=> R = r/4

=> R = 28cm/4

☞ R = 28cm/4 = 7 cm.

Now, CSA of the cone = πrl.

=> 22/7 × 7 cm × 28cm

=> 22 × 28cm

☞ 616 cm²

Therefore, the curved surface area of the cone → 616 cm².

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Answer 2

Answer:

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