What is the radius of a circle with the equation x^2+y^2+2x+4y-9=0
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comparing the eq. x^2+y^2+2x+4y-9 with standard eq. of circle
i.e., x^2+y^2+2gx+2fy+c=0
then, 2g = 2,g = 1
and, 2f = 4,f = 2
and, c = -3
hence, centre = (-g,-f) = (-1,-2)
and, radius(square) = g^2+f^2-c
hence, radius = 2
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Answer:
3.741
Explanation:
14sqrt= 3.74165738677
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