Question

What is the radius of geostationary orbit (T= 1 day ) if for the moon T = 27.4 days and radius = 3.8 x 10^8m .(4.2 x 10^7 m)

Answer 1

The centripetal acceleration = Net centripetal force / mass

Net centripetal force =

R

2

GMm

−m(ω)

2

R

ω=

27.3×24×3600

2π

,R=3.8×10

8

,M=5.92×10

2

4

centripetal acceleration =

m

R

2

GMm

−m(ω)

2

R

=

(3.8×10

8

)

2

6.67×10

−11

×5.92×10

2

4

−(

27.3×24×3600

2π

)

2

×3.8×10

8

=2.7×10

−3

m.s

−2