Question

what is the radius of gyration of a thin uniform road of mass M and length L passing through the center and perpendicular to the length

Answer 1

Answer:

√ L/12 = K where K is radius of gyration

Explanation:

I = MK²

moment of inertia of rod about the center and perpendicular of axis is

I = ML²/12

I = MK²

ML²/12 = MK²

√L/12 = K