What is the radius of the circle if the angle of sector is 90degree and the area of the circle is 196²? With solution
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πr^2=196
r^2=196×7/22=98×7/11=686/11
r=7√(14/11)
Area of sector of angle 90 degree=(1/4)×area of circle =(1/4)×196=49 Ans
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