Question

What is the radix of the numbers if the solution to the quadratic equation x2-10x+31=0 is x=5 and x=8 ?

Answer 1

p(x)=x2-10x+31 at x=5
=(5)2-10(5)+31
=10-50+31
=-40+31
=-9


p(x)=x2-10x+31 at x=8
=(8)2-10(8)+31
=16-80+31
=-64+31
=-33