what is the range of projection and how it changes with the angle of projection
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Range = (v^2)sin2(theta)/g
Max height =( v^2)sin^2(theta)/2g
Equate : 4* (max height)=(range)
U get cot (theta)=1
Theta =45°
Max height =( v^2)sin^2(theta)/2g
Equate : 4* (max height)=(range)
U get cot (theta)=1
Theta =45°
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