Question

What is the range of the function f(x) = 2^(3 sin 4x+1) ?​

Answer 1

Answer:

To Find : Range. Solution: 3 sin (4x) + 1. -1 ≤ sin (4x) ≤ 1. ⇒ - 3 ≤ 3sin (4x) ≤ 3. ⇒ - 3 + 1 ≤ 3sin (4x) ≤ 3 ...

Step-by-step explanation:

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