Question

What is the range of the function f(x)=2^3sin4x+1 ?

Answer 1

Given  : f(x) =  $2^{3\sin{4x}+1}$

To Find :   Range

Solution:

$f(x) = 2^{3\sin{4x}+1}$

3 sin (4x) + 1

-1 ≤ sin (4x) ≤ 1

⇒ - 3 ≤ 3sin (4x) ≤  3

⇒  - 3 + 1  ≤ 3sin (4x) ≤  3 + 1

⇒  - 2  ≤ 3sin (4x) ≤   4

$f(x) = 2^{3\sin{4x}+1}$

2⁻² ≤  f(x) ≤   2⁴

f(x) = [2⁻²  , 2⁴]

= [1/4  , 16]

Range of  $f(x) = 2^{3\sin{4x}+1}$   is   [1/4  , 16]

Learn More:

Let A={1,2,3,4,...,45} and R be the relation defined as “is square of ”

brainly.in/question/9259297

Graph the following Piecewise function. Then determine the domain ...

brainly.in/question/23634530

Answer 2

Step-by-step explanation:

please mark as BRAINEST