Question

What is the range of the principal value of cot−1x?

Answer 1

Answer:

Therefore, cot−1 x = nπ + α, where, (α ≠ 0, – π/2 ≤ α ≤ π/2) and ( - ∞ < x < ∞ ). Therefore, principal value of cot−1 √3 is π/6 and its general value = nπ + π/6.

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