Question

what is the range of x²-2x-15/x-5​

Answer 1

Answer:

x2−2x−15=0x2−2x−15=0

a=1,b=−2,c=−15a=1,b=−2,c=−15

x1,2=−b±b2−4ac−−−−−−−√2ax1,2=−b±b2−4ac2a

x1,2=−(−2)±(−2)2−4∗1∗(−15)−−−−−−−−−−−−−−−−−√2∗1x1,2=−(−2)±(−2)2−4∗1∗(−15)2∗1

x1,2=2±4−4∗(−15)−−−−−−−−−−−√2x1,2=2±4−4∗(−15)2

x1,2=2±4+60−−−−−√2x1,2=2±4+602

x1,2=2±64−−√2x1,2=2±642

x1,2=2±82x1,2=2±82

x1=2+82∨x2=2−82x1=2+82∨x2=2−82

x1=102∨x2=−62x1=102∨x2=−62

x1=5∨x2=−3x1=5∨x2=−3