English, asked by seemaviresh1982, 8 months ago

what is the range of y=cosec^-1(x)​

Answers

Answered by XxItzkillergirlXx
18

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Derivatives of inverse trignometric function:-

 \rightarrow f(x)=cosec^-1

 \rightarrow \: f'(x)= \frac{ - 1}{x \sqrt{ {x}^{2} - 1 }  }

 \rightarrow \: Range= |x|  > 1

Answered by NamirasabaNS
0

Answer:

Explanation:the graphs of y = cosec x and y = cosec–1 x are given in Fig 2.3 (i), (ii). range could be any of the intervals [– π, 0] – { 2 −π }, [0, π] – { 2 π }, [π, 2π] – { 3 2 π } etc

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