Question

What is the rate of diffusion of hydrogen and deuterium are in the ratio

Answer 1

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Answer 2

Answer:

The ratio of rate of effusion of hydrogen and deuterium will be 1.414.

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

We are given:

Molar mass of hydrogen,$H_2$= 2 g/mol

Molar mass of deuterium $D_2$= 4 g/mol

By taking their ratio, we get:

$\frac{Rate_{H_2}}{Rate_{D_2}}=\sqrt{\frac{M_{H_2}}{M_{D_2}}}$

$\frac{Rate_{H_2}}{Rate_{D_2}}=\sqrt{\frac{4}{2}}\\\\\frac{Rate_{H_2}}{Rate_{D_2}}=1.414$

Hence, the ratio of rate of effusion of hydrogen and deuterium will be 1.414.