Question

what is the rate of interest which yields an interest of rs 560 on a sum of rs 28000 after 2 years?​

Answer 1

Step-by-step explanation:

r = 560 × 100÷ 28000×2

r = 56000÷ 56000

r = 1%

Answer 2

${\fbox{\fbox{\fbox{\fbox{\fbox{\huge\sf\purple{AnsWeR}}}}}}}$

$\large \sf{ According\:to\: question}$

t = 2 years

p = 28000

interest = 560

$\sf{560 = 28000xRx2/100}$

$\sf{560x100 = 56000xR}$

$\sf{\frac{56000}{56000 }= R}$

R = 1

Rate is 1 %.