Question

What is the ratio between the rate of decomposition of n2o5 to rate of formation of no2?

Answer 1

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  2N2O5(g) ->4NO2(g)  +  O2(g) The rate of disappearance of N2O5(g) at a certain temperature is 0.016 mol.L-1min-1. What is the rate of formation of NO2(g) (in mol.L-1.min-1) at this...

  2N2O5(g) ->4NO2(g)  +  O2(g) 
The rate of disappearance of N2O5(g) at a certain temperature is 0.016 mol.L-1min-1.

Answer 2

Answer: The ratio between the rate of decomposition of $N_2O_5$ o rate of formation of $NO_2$ is 2:1.

Explanation;

$2N_2O_5\rightarrow 4NO_2+O_2$

Rate of decomposition of the $N_2O_5$:

$R_1=-\frac{1}{2}\frac{d[N_2O_5]}{dt}$..(1)

Rate of decomposition of the $NO_2$:

$R_2=\frac{1}{4}\frac{d[NO_2]}{dt}$..(2)

Divide (1) and (2)

$\frac{R_1}{R_2}=\frac{-\frac{1}{2}\frac{d[N_2O_5]}{dt}}{\frac{1}{4}\frac{d[NO_2]}{dt}}=\frac{2}{1}$

The ratio between the rate of decomposition of $N_2O_5$ o rate of formation of $NO_2$ is 2:1.