What is the ratio between the rate of decomposition of N2O5 to the rate of formation of NO2
Answers
Answered by
1
The decomposition of N2O5 is as follows,
N2O5 = 2NO2
rate of disappeaence of N2O5 = d[N2O5]/dt
rate of appearance of NO2 = d[NO2]/2*dt
therefore the ratio is 1:2
N2O5 = 2NO2
rate of disappeaence of N2O5 = d[N2O5]/dt
rate of appearance of NO2 = d[NO2]/2*dt
therefore the ratio is 1:2
Similar questions