Question

What is the ratio in which the point
(3/5, 11/5)
divides
the line segment joining the points A(3, 5) and
B(-3,-2)​

Answer 1

Answer:

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Answer 2

Answer:

If any point (x, y) divides the line joining points (x1,y1) and (x2, y2) in the ratio m : n then,

x= (mx2+nx1)/(m+n)

y= (my2+ny1)/(m+n)

Here, x= 3/5 and y= 11/5

x1= 3; y1= 5; x2= -3; y2= -2

3/5 =(-3m+3n)/(m+n)

m+n=(-3m+3n)/(3/5)—-(1)

11/5=(-2m+5n)/(m+n)

m+n = (-2m+5n)/(11/5) —-(2)

From (1) and (2)

(-3m+3n)/(3/5) = (-2m+5n)/(11/5)

3m=2n

m/n = 2/3

Ans: Point C divides the line 2:3 ratio

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