what is the ratio of area of orbit of first excited state of electron to the area of orbit of ground level for hydrogen atom
Answers
Answered by
1
the ratio of the area is 16.1
we know that,
the square of radius of the orbit is directly proportionat to power of four of the number of state
x2×n4
where,n is the number of state
the hydrogen for excited state
A1×n4_1
here,n=2for excited state.
The area of hydrogen for ground state
A0×n4_0
Here n=1 for ground state.
Now, The ratio of areas between the electron orbit for the first excited state to the ground state for the hydrogen atom isA1_A0=(n1_no)4
à1_à0=(2_1)4
a1_à0=16_1
Similar questions
English,
6 months ago
Environmental Sciences,
1 year ago