what is the ratio of averege kinetic energy of oxygen molecule at 0° and 273°C.
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avg. kinetic energy = √T1/√T2
= √0°C/273°C
= √273/546
= √1/2
= 1/√2
therefore,, the ratio of avg.kinetic energy of O2 molecule is 1:√2
hope u mark as brainliest..
= √0°C/273°C
= √273/546
= √1/2
= 1/√2
therefore,, the ratio of avg.kinetic energy of O2 molecule is 1:√2
hope u mark as brainliest..
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