Question

What is the ratio of distance of 3rd nearest
neighbour to 2nd nearest neighbour in body
centered cubic lattice? (root 2 = 1.41)​

Answer 1

Answer:

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Explanation:

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Answer 2

The ratio of the 3rd nearest neighbour and 2nd nearest neighbour in BCC is 1.41 ( $\sqrt{2}$).

Explanation:

• In BCC (body centered cubic) lattice, 8 atoms are arranged at the corner of the cell, and an atom is present at the center of the body.
• A total of 9 lattice points are present.
• The second nearest neighbour in BCC is along the edge length and has a separation of a.
• The third nearest neighbour is along the edge diagonal, and has a separation of $a\sqrt{2}$.
• Their ratio will be: 1.41

        $\frac{a\sqrt{2}}{a} =\frac{\sqrt{2}}{1} =1.41$