Question

what is the ratio of escape velocity to critical velocity​

Answer 1

Answer:

Escape velocity= √(2GM/R)

Critical velocity= √(GM/(R+h)

ratio will give you answer as √(2(R+h)/R

Answer 2

Answer:

Escape velocity = √2 × circular orbital velocity. This comes from Newtons law of universal gravitation, F=GMm/R^2. For a circular orbit, the centrifugal force must be equal to the gravitational force, so mV^2/R=GMm/R^2, so orbital velocity=√(GM/R).

On the surface of the Earth, the escape velocity is about 11.2 km/s, which is approximately 33 times the speed of sound (Mach 33) and several times the muzzle velocity of a rifle bullet (up to 1.7 km/s). However, at 9,000 km altitude in "space", it is slightly less than 7.1 km/s.