what is the ratio of force of attraction between two bodies kept in the air and the same distance apart in water
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we know ,
according to coloumbs law
F=Ko.Qq/r^2
where Ko =1/4pi. € o
where € o is permitivity of medium in air
now,
permittivity of medium in water =€ o. €
where € is relative permitivity of medium .
hence ,
K=1/4pi. € o €=Ko/€
now,
F"=KQq/r^2
=KoQq/€ r^2
divided both forces ,
F/F"=€
according to coloumbs law
F=Ko.Qq/r^2
where Ko =1/4pi. € o
where € o is permitivity of medium in air
now,
permittivity of medium in water =€ o. €
where € is relative permitivity of medium .
hence ,
K=1/4pi. € o €=Ko/€
now,
F"=KQq/r^2
=KoQq/€ r^2
divided both forces ,
F/F"=€
Beastmaster64:
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