what is the ratio of force of attraction between two bodies kept in air and the same distance a part in water (need it for exam)
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the force of attraction kept in the air is maximum than in water....
its 3 by 2 ratio
its 3 by 2 ratio
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Let Charges on the two bodies be q1 and q2, r is the distance between two particles, F= force of attraction between the two particles
According to coulombs Law
in air----- F1 =(1/4 pi Epsilon0)*(q1*q2/r*r)
in water----F2 =(1/4 pi Epsilon0*Epsilon water)*(q1*q2/r*r)
so, F1/F2=Epsilon water : 1
Hope that helps, Good Luck :-)
According to coulombs Law
in air----- F1 =(1/4 pi Epsilon0)*(q1*q2/r*r)
in water----F2 =(1/4 pi Epsilon0*Epsilon water)*(q1*q2/r*r)
so, F1/F2=Epsilon water : 1
Hope that helps, Good Luck :-)
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