what is the ratio of inradius and circumradius of right angled triangle
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As the triangle is correct calculated triangle so the circum sweep is a large portion of the hypotenuse and it being isosceles it might be equivalent of the opposite attracted to AC So, in triangle ABC, BD is the circum radius and OD is the in radius.
Presently, triangle BOF is likewise an isosceles right calculated triangle on the grounds that OF=BF=OE. So, OB = 2√2OF
So, ratio of In radius and Circum radius = OFBDOFBD= OFBO+ODOFBO+OD = OFBO+OFOFBO+OF= OF2√OF+OFOF2OF+OF= 12√+1
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