what is the ratio of inradius and circumradius of right angled triangle
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Let ABC a right angled triangle right angle at C then
inradius r=(s-a)tan(A/2)=(s-b)tan(B/2)=(s-c)tan(C/2) where 's' is the semi perimeter
since ∠C=90 degrees
r=s-c and R=abc/4Δ
Δ=1/2 ab
∴ 2R=c
∴r+2R=c
inradius r=(s-a)tan(A/2)=(s-b)tan(B/2)=(s-c)tan(C/2) where 's' is the semi perimeter
since ∠C=90 degrees
r=s-c and R=abc/4Δ
Δ=1/2 ab
∴ 2R=c
∴r+2R=c
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