what is the ratio of KMnO4
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KMnO
4
+7
acidicmedium
Mn
+2
+2
K
2
Cr
2
O
7
+6
acidicmedium
Cr
+3
+3
Sn
+4
+4
reducingagent
Sn
+2
+2
Number of equivalents =moles×nf
n(Sn
+4
)=0.1
nf(Sn
+4
)=2
Equating number of equivalents of KMnO
4
and Sn
+4
n
1
nf
1
=n
2
nf
2
0.1×2=5n
2
n
21
=0.04
Equating number of equivalents K
2
Cr
2
O
7
and Sn
+4
n
1
f
1
=n
2
2f
2
2
0.1×2=6n
22
n
22
=
3
0.1
Ratio of moles of KMnO
3
and K
2
Cr
2
O
7
=
0.1
0.04
=
5
6
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