Question

what is the ratio of maximum range obtained by a projectile to its
maximum hight
​

Answer 1

Answer:

R=u^2Sin2Q /g

Rmax=u^2/g [at Q=45°]

H=u^2sin^2Q/g

H=u^2(sin45°)/2g

H=u^2/4g

Rmax /H=4