Question

what is the ratio of maximum range obtained by a projectile to its maximum height ?​

Answer 1

$\underline{\boxed{\bold{Question}}}$

• What is the ratio of maximum range obtained by a projectile to its maximum height ?​

$\underline{\boxed{\bold{Answer}}}$

For θ = 45° height of projectile is maximum.

$= H_{max} =\frac{u^{2} sin^{2}\theta}{g} \\= H_{max} =\frac{u^{2} sin^{2}45}{g} \\\\= H_{max} =\frac{u^{2}}{2g}$

$Range = R\\\\= R = \frac{u^{2}sin^{2}2\theta }{g} \\\\=R = \frac{u^{2}sin^{2}90 }{g} \\\\= R_{max} = \frac{u^{2}}{g}$

Ratio of H : R = 1 : 2

Hope this helps u..../

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