Question

what is the ratio of number of arrangements of all letter of the word ASHOK and GEETA.​

Answer 1

Answer:

Then the number of arrangements is 5! 2! Next, we have to find the ratio of the number of arrangements of the letters in the words ASHOK and GEETA

Answer 2

Answer:

Ratio

$= \frac{2}{1}$

Step-by-step explanation:

Arrangements:-

1. ASHOK

5! ways

2. GEETA

5! ways but E is repeating twice, so we should divide 5! by 2!

i.e.

$\frac{5!}{2!} = \frac{5 \times 4 \times 3 \times 2!}{2!} = 5 \times 4 \times 3$

Ratio

$\frac{5!}{5 \times 4} = \frac{5 \times 4 \times 3 \times 2 \times 1}{5 \times 4 \times 3} = \frac{2}{1}$