What is the ratio of number of electrons gained by acidified kmno4 and acidified k2cr2o7 in the reaction given below
a.5:6 b)?
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3
Explanation:
oxidant in the reaction given below: (i). 3. 2. 5. PCl Cl ... Sol: Calculate the oxidation numbers , find the loss/gain ..... caffeine (C8H20N4O2 )? ..... by acidified KMnO4 will be equal to.
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1
Answer:
Explanation: kmno4=-1+(mn)+4(-2)=0
mn=+7
k2Cr2o7=-2+2(Cr)-14
cr=+12
in 1st rxn electron gained=7-2 [2= after rxn oxidation no]
in 2nd rxn electron gained=12-2(3)
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