Question

What is the ratio of number of moles of reactants to the number of moles of products in the equation: H2S (g) + SO2 (g) = S (s) + H2O (l)

Answer 1

Answer:

if 2 moles of H2S forms 3 moles of S, then 1/2 mole of H2 forms 3/4 mole of S. If we take SO2 , o.5 moles will require 1 mole of H2S to completely react.

Answer 2

Answer:

The ratio of the number of moles of reactants to the number of moles of products is 3:5.

Explanation:

The reaction given in the question is as follows;

      H₂S(g)+SO₂(g)⇒S(s)+H₂O(g)                   (1)

Where,

H₂S=hydrogen sulfide

SO₂=sulphur dioxide

S=sulphur

H₂O=water

Now after balancing all the elements and compounds in equation (1) we get;

2H₂S(g)+SO₂(g)⇒3S(s)+2H₂O(g)                (2)

Now,

The total number of moles of the reactant i.e.H₂S and SO₂ =3

The total number of moles of the product i.e.S and H₂O =5

Now as per the question, the ratio of the number of moles of reactants to the number of moles of products is 3:5.

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