Question

What is the ratio of stimulated emission to spontaneous emission at a temperature of 250 degree C for the sodium D line

Answer 1

Answer:

Stimulated emission occurs when an atom or molecule in an energy level above the ground state interacts with a photon that has energy equal to that between the atom or molecule's current energy level and a lower energy level.

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Answer 2

Answer:

The ratio between the stimulated emission and spontaneous emission = $5.329$ x $10^{-21}$.

Explanation:

Given data

The temperature, T = 250° C = (250 + 273)K = 523 K

$\frac{Stimulated emission}{Spontaneous emission} = \frac{1}{e^{hv/kt}-1 } = \frac{1}{e^{hc/kTλ} -1}$

                            = $\frac{1}{exp\frac{6.626* 10^{-34}*3*10^{8} }{1.38*10^{-23}*523*5.9*10^{-7} -1 } }$

                           = 5.329 x $10^{-21}$

So, the ratio between the stimulated emission and spontaneous emission = $5.329$ x $10^{-21}$.

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