Physics, asked by rathodsweta3525, 1 month ago

What is the ratio of the distance covered by the particle in the fourth and third seconds when the motion starts from a steady state stationary position with constant entry?

A- 7/5
B - 7/3
C - 5/7
D - 3/7​

Answers

Answered by mitrakshim
0

Answer:

ratio of distance traveled in 4th sec. to 3rd sec =2×3−12×4−1=57.

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