Physics, asked by ambicaparasa3662, 1 year ago

What is the ratio of the frequencies of the notes emitted (1) by an open pipe
and (ii) by a closed pipe of the same length.

Answers

Answered by prmkulk1978
0

Answer:

The ratio of frequencies of notes emitted by open pipe and close pipe is  2:1

Explanation:

Fundamental frequency in open pipe of length l is :

n1= V/2l

Fundamental frequency in closed pipe of length l is :

n=V/4l

∴ The ratio of frequencies of notes emitted by open pipe and close pipe is :

n1/n = \frac{V/2l}{V/4l}

=4l/2l

=2: 1

Answered by vidhi6013
0

Answer:

the above is your answer

I check it

it's correct

(Brainly guru)

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