what is the ratio of the interior angles of a pentagon and a decagon
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Answered by
65
each interior angle of Pentagon=(2*5-4)*90/5
=(10-4)*18
=6*18
=108
each interior angle of decagon =(2*10-4)*90/10
=(20-4)*9
=16*9
=144
the ratio=108/144
=9/12
=3/4
=(10-4)*18
=6*18
=108
each interior angle of decagon =(2*10-4)*90/10
=(20-4)*9
=16*9
=144
the ratio=108/144
=9/12
=3/4
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Answered by
8
STEP 1: Find the sum of the interior angles of a pentagon
A pentagon has 5 sides.
Sum of the interior angles = ( n - 2) x 180
Sum of the interior angles = ( 5 - 2) x 180
Sum of the interior angles = 540°
STEP 2: Find one interior angle:
one interior angle = 540 ÷ 5 = 108
STEP 3: Find the sum of interior angles of a decagon
A decagon has 10 sides
Sum of the interior angles = ( n - 2) x 180
Sum of the interior angles = ( 10 - 2) x 180
Sum of the interior angles = 1440°
STEP 4: Find one interior angle:
one interior angle = 1440 ÷ 10 = 144
STEP 5: Find the ratio:
Pentagon : Decagon = 108 : 144
Simplify:
Pentagon : Decagon = 3:4
Answer: The ratio is 3 : 4
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