Question

what is the ratio of the prime numbers and composite numbers from the set of natural numbers from 1 to 20? please answer fast

Answer 1

prime-numbers
P is the count of prime numbers in Z
And so, Z−P=NP is the count of non-prime numbers in Z what is the answer of this equation: P/NP
I thought that question and I made that proof, if I'm mistake please correct me.

E=Even, O=Odd
1,2,3,4,⋯Z
O,E,O,E,⋯

Clearly there is Z/2 count of Even, and Z/2 count of Odd numbers exist.

If any number in Z can write as M×N it is non-prime number, otherwise it's prime number M×N can be one of that 4 combinations:

E×E=E
E×O=E
O×E=E
O×O=O

So, M×N is 34 in ratio of Even numbers, and 14 ratio of Odd.

Even Numbers: 34 * NP
Odd Numbers: 14 * NP

Even Numbers: 0∗P
Odd Numbers : P

There is equal counts of even and odd numbers, so; 34∗NP+0=1/4∗NP+P
14∗NP=P
NP=2∗P

If this equation is true, then non-prime numbers are only double-times of prime numbers.

Answer 2

P is the count of prime numbers in Z
And so, Z−P=NP is the count of non-prime numbers in Z what is the answer of this equation: P/NP

I thought that question and I made that proof, if I'm mistake please correct me.

E=Even, O=Odd
1,2,3,4,⋯Z
O,E,O,E,⋯

Clearly there is Z/2 count of Even, and Z/2count of Odd numbers exist.

If any number in Z can write as M×N it is non-prime number, otherwise it's prime number M×N can be one of that 4combinations:

E×E=E
E×O=E
O×E=E
O×O=O

So, M×N is 34 in ratio of Even numbers, and 14 ratio of Odd.

Even Numbers: 34 * NP
Odd Numbers: 14 * NP

Even Numbers: 0∗P
Odd Numbers : P

There is equal counts of even and odd numbers, so; 34∗NP+0=1/4∗NP+P
14∗NP=P
NP=2∗P

If this equation is true, then non-prime numbers are only double-times of prime numbers. Please check my proof.