What is the ratio of the velocities of CH₄ and O₂ molecules so that they are associated with de-Broglie waves of equal wavelengths?
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Answer:
2:1 is the required ratio.
Explanation:
De-Broglie's wavelength = h/mv
Mass of CH₄ = 16 g.
Mass of O₂ = 32 g.
Since, the wavelength is equal,
h / Mass of CH₄ * Velocity of CH₄ = h / Mass of O₂ * Velocity of O₂
h and h get canceled. ("h" is known as Planck's constant)
1 / Mass of CH₄ * Velocity of CH₄ = 1 / Mass of O₂ * Velocity of O₂
Velocity of CH₄ / Velocity of O₂ = Mass of O₂ / Mass of CH₄
Velocity of CH₄ / Velocity of O₂ = 32 / 16
Velocity of CH₄ / Velocity of O₂ = 2 / 1
Therefore the ratio Velocity of CH₄ : Velocity of O₂ = 2 : 1.
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