Question

what is the ratio of time taken to travel its 1st 2nd and 3rd metre fOr a freely falling body​

Answer 1

Answer:

1 : (√2 - 1) : (√3 - √2)

Explanation:

Time taken to travel 1st metre

• x = ut + 0.5at²
• 1 = 0.5gt²
• t = √(2/g)

Time taken to travel 1st "2 m" is

• 2 = 0.5gT²
• T = √(4/g)

Time taken to travel 2nd "1 m" is then

• t' = T - t
• t' = √(4/g) - √(2/g)

Time taken to travel 1st "3 m" is

• 3 = 0.5gT'²
• T' = √(6/g)

Time taken to travel 3rd "1 m" is then

• t'' = T' - T
• t'' = √(6/g) - √(4/g)

Ratio of times:

• t : t' : t''
• √(2/g) : [√(4/g) - √(2/g)] : [√(6/g) - √(4/g)]
• √2 : (√4 - √2) : (√6 - √4)
• 1 : (√2 - 1) : (√3 - √2)