Question

What is the ratio of total kinetic energy of 8 g of Helium and 8 g of oxygen at 27°C.


​

Answer 1

Answer:

The kinetic energy of a gas at a given temperature T is given by the expression:  

KE=  

2

3

​  

nRT=  

2

3

​  

×  

M

w

​  

RT.  

Here, n is the number of moles of a gas, w is the mass of gas and M is the molar mass of a gas. Thus, the kinetic energy of a gas molecule is inversely proportional to the molar mass of the gas molecule.

K.E  

H  

2

​  

 

​  

 

K.E  

O  

2

​  

 

​  

 

​  

=  

y

x

​  

=  

M  

O  

2

​  

 

​  

 

M  

H  

2

​  

 

​  

 

​  

=  

32

2

​  

=  

16

1

​  

 

Hence, x=1.

Explanation:

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